根据空间直线的两点式:(x-x1)/(x2-x1) = (y-y1)/(y2-y1) = (z-z1)/(z2-z1) ,
可得所求直线方程为:(x+2)/2 = (y-1)/(-2) = (z-3)/(-1) ,
即:(x+2)/2 = (1-y)/2 = 3-z .
怎么求过两点的直线方程?例如两点是(-2,1,3)、(0,-1,2)
怎么求过两点的直线方程?例如两点是(-2,1,3)、(0,-1,2)
数学人气:363 ℃时间:2020-05-08 02:05:03
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