x=v0cosθ×t①
y=v0sinθ×t-
1 |
2 |
故小球运动轨迹方程为:y=xtanθ-
g | ||
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当y=0时,解出x即为水平射程,故x=
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g |
小球运动时间T=
x |
v0cosθ |
2v0sinθ |
g |
由于两个小球A和B的射程相同,故有:
sin2θA=sin2θB⑥
故2θA=π-2θB⑦
由⑤得:TA=
2v0sinθA |
g |
TB=
2v0sinθB |
g |
由⑦⑧⑨可得,TB=
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g |
答:小球B在空中运行的时间为
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g |
1 |
2 |
g | ||
|
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g |
x |
v0cosθ |
2v0sinθ |
g |
2v0sinθA |
g |
2v0sinθB |
g |
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g |
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g |