由题意,
(a+2)^2+(b+3)^2=0
所以a=-2,b=-3
在题为x² +2x-3=0
即(x-1)(x+3)=0
x=1或-3
a² +b² +4a+6b+13=0 a,b为实数 求解x² -ax+b=0
a² +b² +4a+6b+13=0 a,b为实数 求解x² -ax+b=0
数学人气:115 ℃时间:2019-08-28 10:22:26
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