已知a^2+9b^2+6a+10=0,求代数式(6a^m+2 b^n+2-4a^m+1 b^n+1+2a^m b^n)除以(-2a^m b^n)
已知a^2+9b^2+6a+10=0,求代数式(6a^m+2 b^n+2-4a^m+1 b^n+1+2a^m b^n)除以(-2a^m b^n)
已知a^2+9b^2+6a-6b+10=0
已知a^2+9b^2+6a-6b+10=0
数学人气:566 ℃时间:2019-10-08 08:15:29
优质解答
a^2+9b^2+6a-6b+10=0a^2+6a+9+9b^2-6b+1=0(a+3)^2+(3b-1)^2=0(a+3)^2=0,(3b-1)^2=0a=-3b=1/3[6a^(m+2) b^(n+2)-4a^(m+1) b^(n+1)+2a^m b^n]/(-2a^m b^n)=[6a^2*a^m*b^2* b^n-4a*a^m*b* b^n+2a^m b^n]/(-2a^m b^n)=...
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