-5log9为底4的对数+log3为底(32/9)的对数-5^(log5为底3的对数)-（1/64）^(-2/3)

-5log9(4)+log3(32/9)-5^[log5(3)]-(1/64)^(-2/3)
=-5[log3(4)]/log3(9)]+log3(32)-log3(9)-3-64^(2/3)
=-5log3(2)+5log3(2)-2-3-16
=-21有公式：a^[loga(N)]=N有公式(换底公式)：loga(b)=[logc(b)]/[logc(a)]