求x^2*e^(1/x^2)的极限,当x趋向于0时
求x^2*e^(1/x^2)的极限,当x趋向于0时
即x的平方乘以e的x方分之一的极限,当x趋向于0时.
能用洛比达法则做一下吗？
这样，化成x^2
--- 分子分母分别求导
e^(1/x^2)
即x的平方乘以e的x方分之一的极限,当x趋向于0时.
能用洛比达法则做一下吗？
这样，化成x^2
--- 分子分母分别求导
e^(1/x^2)
数学人气：132 ℃时间：2020-03-28 23:25:28
优质解答
e^x=1+x+(1/2)*x^2+……+x^n/(n!)+……lim(x^2*(e^(1/x^2)) |x->0= lim [x^2(1+1/x^2+(1/x^2)^2/2+……)] |x->0= lim(x^2+ 1 + 1/(2*x^2) + ……) |x->0=0+ 1 + 无穷 + 无穷 + ……=无穷极限不存在...
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