原式=-[(2m+4m+6m+……+2012m)-(m+3m+5m+……+2011m)]
=-[(2m-m)+(3m-2m)+……+(2012m-2011m)]
=-[m+m+……+m] 有2012/2=1006个m
=-1006m
(m+3m+5m+...+2011m)-(2m+4m+6m+...+2012m)=多少
(m+3m+5m+...+2011m)-(2m+4m+6m+...+2012m)=多少
数学人气:369 ℃时间:2020-01-28 02:02:35
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