cosx |
1−x |
所以y′=
(cosx)′•(1−x)−cosx•(1−x)′ |
(1−x)2 |
=
(−sinx)•(1−x)+cosx |
(1−x)2 |
cosx−sinx+xsinx |
(1−x)2 |
故选B.
cosx |
1−x |
cosx+sinx+xsinx |
(1−x)2 |
cosx−sinx+xsinx |
(1−x)2 |
cosx−sinx+xsinx |
1−x |
cosx+sinx−xsinx |
(1−x)2 |
cosx |
1−x |
(cosx)′•(1−x)−cosx•(1−x)′ |
(1−x)2 |
(−sinx)•(1−x)+cosx |
(1−x)2 |
cosx−sinx+xsinx |
(1−x)2 |