X^2-y^2-x-y=0 和4x^2-y^2+2y-1=0 的方程组怎么解

X^2-y^2-x-y=0.(1)4x^2-y^2+2y-1=0 .(2)根据（1）:(x+y)(x-y)-(x+y)=0(x+y)(x-y-1)=0x+y=0.(3)或x-y-1=0.(4)根据（2）:(2x)^2-(y-1)^2=0(2x+y-1)(2x-y+1)=02x+y-1=0.(5）或2x-y+1=0.(6)(3),(5)联立方程,解得：x=0,y=...