∵OM平分∠AOB，ON平分∠COD
设∠AOM=∠MOB=x，∠CON=∠NOD=y
∵∠MON=90°，∠BOC=26°
∴∠NOC+∠BOC+∠BOM=90°
∴x+y+26°=90°
∴x+y=64°
而∠AOD=2x+2y+26°=2×64°+26°=154°．
故答案为154°．
如图所示，OM平分∠AOB，ON平分∠COD，∠MON=90°，∠BOC=26°，求∠AOD的度数．
如图所示，OM平分∠AOB，ON平分∠COD，∠MON=90°，∠BOC=26°，求∠AOD的度数．
数学人气：197 ℃时间：2019-09-29 02:36:17
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