原式=lim [3^n/4^(n+1)+1/4]/[3^(n+1)/4^(n+1)+1] 上下同时除以4^(n+1)
=lim [1/4*(3/4)^n+1/4]/[(3/4)^(n+1)+1]
=(0+1/4)/(0+1)
=1/4
lim (3^n+4^n)/[3^(n+1)+4^(n+1)] [数列极限]
lim (3^n+4^n)/[3^(n+1)+4^(n+1)] [数列极限]
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数学人气：734 ℃时间：2019-10-19 18:23:33
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