1/a+1/b+1/c=13/210=(1+2+10)/20
13/210=(1+2+10)/210=1/210+1/105+1/21
13/210=(1+5+7)/210=1/210+1/42+1/30
13/210=(2+5+6)/210=1/105+1/42+1/35
所以有3组
选C
设a,b,c为不相等的正整数,满足11/a+11/b+11/c=143/210的数组(a,b,c)有( )个?
设a,b,c为不相等的正整数,满足11/a+11/b+11/c=143/210的数组(a,b,c)有( )个?
A.1 B.2 C.3 D.无数个
A.1 B.2 C.3 D.无数个
数学人气:129 ℃时间:2020-05-08 13:30:09
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