∫（√a-√x）平方dx 上下限 a 求怎么算

∫[0→a] (√a - √x)² dx
=∫[0→a] (a - 2√(ax) + x) dx
=ax - 2(2/3)(√a)x^(3/2) + (1/2)x² |[0→a]
=a² - (4/3)a² + (1/2)a²
=(1/6)a²
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