已知x+3xy-y=0求代数式x-2xy-y分之2x-14xy-2y的值

已知x+3xy-y=0
则x-y=-3xy
所以x-2xy-y分之2x-14xy-2y
=[(x-y)-2xy]/[2(x-y)-14xy]
=[-3xy-2xy]/[2*(-3xy)-14xy]
=(-5xy)/(-20xy)
=1/4你做过了吗写反了x-2xy-y分之2x-14xy-2y=[2(x-y)-14xy]/[(x-y)-2xy]=[2*(-3xy)-14xy]/[-3xy-2xy]=(-20xy)/(-5xy)=4有一个人也做过了但和你的答案不一样他的错了x-7xy-y=-10xy他等于-5xy获得物品你挺多的你是美女吧，怎么这么细致。你是白痴