已知abc不等于0,且a/b=b/c=c/a,则(3a+2b+c)/ (a-2b-3c)=________
已知abc不等于0,且a/b=b/c=c/a,则(3a+2b+c)/ (a-2b-3c)=________
答案只有一个结果：-2/3.可是如果设a/b=b/c=c/a=k,那a=bk,b=ck,c=ak,三个一加,得a+b+c=(a+b+c)k,所以a+b+c=0或k=1,那不是有两种情况?
答案只有一个结果：-2/3.可是如果设a/b=b/c=c/a=k,那a=bk,b=ck,c=ak,三个一加,得a+b+c=(a+b+c)k,所以a+b+c=0或k=1,那不是有两种情况?
数学人气：489 ℃时间：2019-11-10 08:54:33
优质解答
a/b=b/c=c/a=>b*b=a*c,c*c=a*b=>b^4=a^2*c^2=a^3*b=>a^3=b^3=>a=b,同理得b=c,那么a=b=c,得 -3/2,且abc不=0=》a+b+c不=0
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