∫dx/(1+x^2)上限根号3下限-1求定积分
∫dx/(1+x^2)上限根号3下限-1求定积分
数学人气：724 ℃时间：2019-10-27 11:49:44
优质解答
因为(arctanx)的导数是1/(1+x^2),所以∫dx/(1+x^2)=arctanx,又其下/上限为[-1,3^0.5],根据定积分基本规则,可得该定积分=arctan(3^0.5)-arctan(-1)=π/3-(-π/4)=7π/12
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