设m>n>0,m^2+n^2=4m,则mn分之m^2-n^2的值等于

m^2+n^2=4m
则mn分之m^2-n^2
=(m^2-n^2)/mn
=(m+n)(m-n)/mn
=√[(m+n)²(m-n)²]/mn
=√[(m²+2mn+n²)(m²-2mn+n²)]/mn
无法计算下去
题目应该有问题!似乎真的是题目的问题，应是m^2+n^2=4mn你能接着算吗？m^2+n^2=4mn则mn分之m^2-n^2=(m^2-n^2)/mn=(m+n)(m-n)/mn=√[(m+n)²(m-n)²]/mn=√[(m²+2mn+n²)(m²-2mn+n²)]/mn=√(6mn*2mn)/mn=2√3 mn/mn=2√3选择A