若直线3x+4y+k0与圆x平方+y平方-6x+5=0相切,则k等于多少?
若直线3x+4y+k0与圆x平方+y平方-6x+5=0相切,则k等于多少?
数学人气:293 ℃时间:2019-10-10 04:04:35
优质解答
因为圆x^2+y^2-6x+5=0 整理可得(x-3)^2+y^2=4 所以圆的圆心是点(3,0) 半径是2 利用点到直线距离公式 [|3乘3+4乘0+k|/根号下(3^2+4^2)]=2 可解得k=1或k=-19
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