原式=x(x+y)(x-y)/x^2y(x^2+2xy+y^2)
=(x+y)(x-y)/xy(x+y)^2
=(x-y)/xy(x+y)
=(✓3+✓2-✓3+✓2)/(✓3+✓2)(✓3-✓2)(✓3+✓2+✓3-✓2)
=2✓2/2✓3
=✓6/3
已知x=根号3+根号2,y=根号3-根号2求(x^3-xy^2)/(x^4y+2x^3y^2+x^2y^3)
已知x=根号3+根号2,y=根号3-根号2求(x^3-xy^2)/(x^4y+2x^3y^2+x^2y^3)
数学人气:321 ℃时间:2019-08-18 22:02:54
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