tanx=2,则sinx与cosx是同号的,所以sinx*cosx=2/√5*1/√5=2/5
所以
20sinacosa=20*2/5=8
f(x)是以5为周期的奇函数,则f（3）=f（3+5）=-f（-3）=-1
所以f（20sinacosa）=f（8）=-1
若f(x)是以5为周期的奇函数,且f（—3）=1,tanx=2,则f（20sinacosa）=
若f(x)是以5为周期的奇函数,且f（—3）=1,tanx=2,则f（20sinacosa）=
数学人气：778 ℃时间：2020-05-17 01:40:38
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