lim(x趋于1)(x^3-3x^2+2)/(x^3-x^2-x+1)
=lim(x趋于1)(3x^2-6x)/(3x^2-2x-1)
=lim(x趋于1)(6x-6)/(6x-2)
=0/4
=0.
用洛必达法则求lim(x趋于1)(x^3-3x^2+2)/(x^3-x^2-x+1)的极限,
用洛必达法则求lim(x趋于1)(x^3-3x^2+2)/(x^3-x^2-x+1)的极限,
数学人气:681 ℃时间:2020-04-14 20:48:42
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