x/y²·(-y/x²)=-1/(xy)
.
4/(a²-1)·(a-1)/(6a)=2/[3a(a+1)]可以写一下计算过程吗?拜托了x/y²·(-y/x²)=-1/(xy)(分子分母分别约掉一个y和一个x).4/(a²-1)·(a-1)/(6a)=2/[(a+1)(a-1)] ·(a-1)/(3a)=2/[3a(a+1)] (分子分母约掉(a-1) )
计算:x/y²·(-y/x²);4/a²-1·a-1/6a.
计算:x/y²·(-y/x²);4/a²-1·a-1/6a.
数学人气:555 ℃时间:2020-04-02 10:05:11
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