化简求值：[x(xy-1)^2-(xy+2)(2-xy)]除以4分之1xy,其中x=-2,y=5分之1.

[4(xy-1)^2-(xy+2)(2-xy)]除以4分之1xy
=[4x^2乘以y^2-8xy+4-(4-x^2y^2)]除以4分之1xy
=(4x^2乘以y^2-8xy+4-4+x^2y^2)除以4分之1xy
=(5x^2乘以y^2-8xy)除以4分之1xy
=20xy-32
当x=-2,y=5分之1时,
原式=20×（-2）×5分之1-32
=-8-32
=-40