很简单的等差数列问题.
a[]b=b*a+(1+2+3+……+b-1)
=b*a+(b-1)b/2
95[]x=95x+(x-1)x/2=585
最后留下的解是x=5.
对于两个数a与b,规定a【】b=a+(a+1)+（a+2)+(a+3)+.+(a+b-1)已知95【】x=585,求x
对于两个数a与b,规定a【】b=a+(a+1)+（a+2)+(a+3)+.+(a+b-1)已知95【】x=585,求x
拜托了,请尽快告诉我答案.谢谢谢谢!
拜托了,请尽快告诉我答案.谢谢谢谢!
数学人气：950 ℃时间：2020-01-29 09:09:16
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