方程组：(1/x+1)+(2/6y-3)=1 (1/2x-2)-(1/2y-1)=0,解x、y.
方程组：(1/x+1)+(2/6y-3)=1 (1/2x-2)-(1/2y-1)=0,解x、y.
1/（x-1）+2/（6y-3）=1,1/（2x-2)-1/（2y-1)=0，那个错了，
1/（x-1）+2/（6y-3）=1,1/（2x-2)-1/（2y-1)=0，那个错了，
数学人气：949 ℃时间：2019-12-08 19:52:56
优质解答
1/x+1)+(2/6y-3)=0得3y+x-6xy=0,由1 (1/2x-2)-(1/2y-1)=0得y-x=0,所以x=y=0或等于2/3由于x,y均为他母,所以不等于0所以x=y=2/3
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