求下列函数的最小正周期 递增区间和最大值 （1） y=sin2xcos2x （2）y= 2cos

y = 2 sin2x cos2xy = sin4xT = 2π/4 = π/2ymin = -1 at 4x = 2kπ - π/2ymax = 1 at 4x = 2kπ + π/2递增区间[kπ/2 - π/8,kπ/2 + π/8],k∈Z------------------------------------------------------------y...谢谢你！