方程|x-1|=根号(1-(y-1)^2)表示的曲线是什么?
方程|x-1|=根号(1-(y-1)^2)表示的曲线是什么?
答案是两个半圆,为什么?请详解
答案是两个半圆,为什么?请详解
数学人气:788 ℃时间:2020-03-24 18:06:54
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|x-1|=根号(1-(y-1)^2)(x-1)^2=1-(y-1)^2 1-(y-1)^2≥0(x-1)^2+(y-1)^2=1 (y-1)^2≤1(x-1)^2+(y-1)^2=1 0≤y≤2表示以(1,1)为圆心,1为半径的圆答案说是两个半圆的话,答案错了.做出那个答案的人把我上面过程里的≥写...
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