3x+5(x+y)=36
即8x+5y=36.(1)
3y+4(x+y)=36
即4x+7y=36.(2)
(1)-(2)*2得
-9y=-36
y=4
代入(2)得
4x+28=36
4x=8
x=2
解得
x=2
y=4
二元一次方程组3x+5(x+y)=36 3y+4(x+y)=36用加减消元法怎么解
二元一次方程组3x+5(x+y)=36 3y+4(x+y)=36用加减消元法怎么解
数学人气:304 ℃时间:2019-11-07 09:43:49
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