ds/dt=[cost(1+cost)-(1+sint)(-sint)]/(1+cost)²
=(cost+cos²t+sint+sin²t)/(1+cost)²
=(cost+sint+1)/(1+cost)²（cost+sint+1)/(1+cost)² 这个形式有没有办法再化简呢？
怎么求s=(1+sint)/(1+cost)的导数?
怎么求s=(1+sint)/(1+cost)的导数?
数学人气：780 ℃时间：2020-02-04 06:46:25
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