∴2x+y-1=0①，x-2y=0②，
①×2+②，得5x=2，
x=
| 2 |
| 5 |
则y=
| 1 |
| 5 |
∴x2+xy+y2=
| 7 |
| 25 |
若|2x+y-1|+（x-2y）2=0，则x2+xy+y2的值为_．
若|2x+y-1|+（x-2y）2=0，则x2+xy+y2的值为______．
数学人气：451 ℃时间：2020-02-15 08:51:13
优质解答
依题意得：|2x+y-1|=0，（x-2y）2=0
∴2x+y-1=0①，x-2y=0②，
①×2+②，得5x=2，
x=
，
则y=
．
∴x2+xy+y2=
．
∴2x+y-1=0①，x-2y=0②，
①×2+②，得5x=2，
x=
则y=
∴x2+xy+y2=
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