初一上册数学化简计算

初一上册数学化简计算
化简求过程:(1)(4a²b-10b³)+(-3a²b²+10b³)(2) (4x²y-5xy²)-(3xy²-4xy²) (3) 5a²-[ a²+(5a²-2a)-2(a²-3a)](4) 15+3(1-a)-(1-a-a²)+(1-a+a²-a³)(5)(4a²b-3ab)+(-5a²b+2ab) (6)(6m²-4m-3)+(2m²-4m+1)在线等啊!!!!
数学人气:892 ℃时间:2020-04-01 11:02:13
优质解答
(1)(4a²b-10b³)+(-+10b³) (2) (4x²y-5xy²)-(3xy²-4xy²)
=4a²b-10b³-3a²b²+10b³ =4x²y-5xy²-3xy²+4xy²
=a²b =4x²y-4xy²
(3) 5a²-[ a²+(5a²-2a)-2(a²-3a)] (4) 15+3(1-a)-(1-a-a²)+(1-a+a²-a³)
=5a²-[ a²+5a²-2a-2a²+6a] = 15+3-3a-1+a+a²+1-a+a²-a³
=5a²-a²-5a²+2a+2a²-6a =2a+a²+a³+18
=a²-4a
(5) (4a²b-3ab)+(-5a²b+2ab) (6)(6m²-4m-3)+(2m²-4m+1)
= 4a²b-3ab-5a²b+2ab =6m²-4m-3+2m²-4m+1
=-a²b-ab =8m²-8m+1
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