解方程:2x^4-3x^3-x^2-3x+2=0
解方程:2x^4-3x^3-x^2-3x+2=0
数学人气:681 ℃时间:2020-03-16 13:04:42
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答:2x^4-3x^3-x^2-3x+2=0(2x^4-4x^3)+(x^3-2x^2)+(x^2-3x+2)=02(x-2)x^3+(x-2)x^2+(x-1)(x-2)=0(x-2)(2x^3+x^2+x-1)=0所以:x-2=0或者2x^3+x^2+x-1=0解得:x=22x^3+x^2+x-1=0(2x^3-x^2)+2x^2+x-1=0(2x-1)x^2+(2x-1)...
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