解
a与b夹角为60
/a/=√2²+0²=2
/b/=1
a*b=/a//b/cos60=1
/a+2b/
=√(a+2b)²
=√a²+4ab+4b²
=√4+4+4
=√12
=2√3
平面向量a与b夹角为60度,a=(2,0),|b|=1,则|a+2b|=?.
平面向量a与b夹角为60度,a=(2,0),|b|=1,则|a+2b|=?.
数学人气：501 ℃时间：2019-11-18 09:16:27
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