a大于等于1-根号3 小于2
解法:g(x)=-log2()为减函数 则X^2-ax-a在(-∞,1-根号3)上也应为减函数 所以其对称轴a/2要大于等于1-根号3 还有 (X^2-ax-a)在(-∞,1-根号3)上要大于0 所以(1-根号3)^2-a(1-根号3)-a大于0 得解
已知函数f(X)=-log2(X^2-ax-a)在(-∞,1-根号3)上是增函数,求实数a的取值范围.
已知函数f(X)=-log2(X^2-ax-a)在(-∞,1-根号3)上是增函数,求实数a的取值范围.
数学人气:309 ℃时间:2019-08-18 22:28:29
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