已知：2x+3y+z=13,4x^2+9y^2+z^2-2x+15y+3z=82 求：x,y,z的值是多少?

X=3,y=1,z=4
2x+3y+z=13 (1) 4x^2+9y^2+z^2-2x+15y+3z=82 (2)
11 (1)* (2) ------》4x^2+9y^2+z^2-24x-18y-8z+61=0
配方-----》4(x-3)^2+9(y-1)^2+(z-4)^2=0
-----》x=3,y=1,z=4