1、
原式=-(√6-√3)(√6+√3)
=-[(√6)²-(√3)²]
=-(6-3)
=-3
2、
原式=(3×3√2+5√2/5)/32
=(9√2+√2)/32
=10√2/32
=5√2/16
2 到二次根式计算题:1.(√6-√3)(-√3-√6) 2.(3√18+(√50)/5)/32
2 到二次根式计算题:1.(√6-√3)(-√3-√6) 2.(3√18+(√50)/5)/32
数学人气:983 ℃时间:2020-06-21 12:16:29
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