2x^3+(1-√5)x^2-2√5x-√5+5=0,
解得x1=(√5-1)/2,x2,3=土5^(1/4).
解方程2x^3+(1-根号5)x^2-2根号5x-根号5+5=0
解方程2x^3+(1-根号5)x^2-2根号5x-根号5+5=0
2x^3+(1-根号5)x^2-2(根号5)x-根号5+5=0
2x^3+(1-根号5)x^2-2(根号5)x-根号5+5=0
数学人气:402 ℃时间:2019-11-06 21:45:48
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