∫ e^(2x)sin3x dx
= (- 1/3)∫ e^(2x) dcos3x
= (- 1/3)e^(2x)cos3x + (1/3)(2)∫ e^(2x)cos3x dx <=分部积分
= (- 1/3)e^(2x)cos3x + (2/3)(1/3)∫ e^(2x) dsin3x
= (- 1/3)e^(2x)cos3x + (2/9)e^(2x)sin3x - (2/9)(2)∫ e^(2x)sin3x dx <=分部积分
(1 + 4/9)∫ e^(3x)sin3x dx = (2/9)e^(2x)sin3x - (1/3)e^(2x)cos3x
∫ e^(3x)sin3x dx = (9/13)[(2/9)e^(2x)sin3x - (1/3)e^(2x)cos3x] + C
==> ∫ e^(3x)sin3x dx = (1/13)(2sin3x - 3cos3x)e^(2x) + C
猜你喜欢
- 1放在桌面上的书,受到托力和重力的作用,这两个力的施力物体分别是什么
- 2求一篇关于开心的事的作文.
- 3对比实验
- 4An account with this email address already exists
- 5在一段长十分之七千米的路的一侧等距离栽36棵树两端都要栽,相邻两棵树之间的距离是多少米?
- 6谁可以写一篇关于中国名胜古迹的作文.500字
- 7有两个圆形组成的图形就是圆环,这是对的吗?
- 8Well,I don't agree.But I think there will be fewer trees.
- 9电阻超差是什么意思
- 10This product is covered by one or more of the following patents:US5,307,459,US5,434,872,US5,732,