右边=a^3+2c^3=(X+Y+Z)^3+2(X^3+Y^3+Z^3-3XYZ)
=3(x^3+y^3+Z^3+x^2y+x^2z+y^2x+y^2z+z^2x+z^2y),
左边=3ab^2=3(X+Y+Z)(X^2+Y^2+Z^2)
=3(x^3+y^3+Z^3+x^2y+x^2z+y^2x+y^2z+z^2x+z^2y),
所以原等式成立
已知:X+Y+Z=a,X^2+Y^2+Z^2=b^2,X^3+Y^3+Z^3-3XYZ=c^3,求证3ab^2=a^3+2c^3
已知:X+Y+Z=a,X^2+Y^2+Z^2=b^2,X^3+Y^3+Z^3-3XYZ=c^3,求证3ab^2=a^3+2c^3
数学人气:214 ℃时间:2020-04-03 22:23:59
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