求函数y=cosx+cos(x-π/3)的最大值

y=cosx+cos(x-π/3)=cosx+cosxcos(π/3)+sinxsin(π/3)=(3/2)cosx+(√3/2)sinx=√3* [cosx*(√3/2)+sinx*(1/2)] =√3[cosxsin(π/3)+cosxsin(π/3)]=√3sin(x+π/3)所以函数y=cosx+cos(x-π/3)的最大值为√3...