8 |
5 |
=-9-8+2
=-15;
(2)原式=(-3)2004×(-
1 |
3 |
1 |
3 |
=[(-3)×(-
1 |
3 |
1 |
3 |
=12004×(-
1 |
3 |
=-
1 |
3 |
(3)设
1 |
2 |
1 |
3 |
1 |
2005 |
1 |
2 |
1 |
3 |
1 |
2004 |
则原式=a(1+b)-(1+a)•b
=a+ab-b-ab
=a-b
=
1 |
2005 |
8 |
5 |
1 |
3 |
1 |
2 |
1 |
3 |
1 |
2005 |
1 |
2 |
1 |
3 |
1 |
2004 |
1 |
2 |
1 |
2005 |
1 |
2 |
1 |
3 |
1 |
2004 |
8 |
5 |
1 |
3 |
1 |
3 |
1 |
3 |
1 |
3 |
1 |
3 |
1 |
3 |
1 |
2 |
1 |
3 |
1 |
2005 |
1 |
2 |
1 |
3 |
1 |
2004 |
1 |
2005 |