a^2+2a/a^2-6a+9÷a^2-4/a^2-3a-a/a-2
=a(a+2)/(a-3)^2×a(a-3)/(a+2)(a-2)-a/(a-2)
=(a^2)/(a-3)(a-2)-a/(a-2)
=[a^2-a(a-3)]/(a-3)(a-2)
=3a/(a-3)(a-2)
化简:a^2+2a/a^2-6a+9÷a^2-4/a^2-3a-a/a-2
化简:a^2+2a/a^2-6a+9÷a^2-4/a^2-3a-a/a-2
数学人气:179 ℃时间:2020-03-28 20:04:14
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