已知方程(x-5/2)-a=x-1的解满足不等式组{(-1/2)x≤1,x-2≤0,求a的取值范围.
已知方程(x-5/2)-a=x-1的解满足不等式组{(-1/2)x≤1,x-2≤0,求a的取值范围.
数学人气:309 ℃时间:2020-04-16 15:55:36
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由不等式组(-1/2)x≤1 => x≥-2 x-2≤0 =>x≤2知: -2≤x≤2方程(x-5)/2-a=x-1,化简得: a=-(x+3)/2因为-5/2≤-(x+3)/2≤-1/2所以...
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