2x-y+2z=8(1)
y+2z=-2(2)
3x+y-4z=1(3)
(1)+(2)
2x+4z=6
x+2z=3(4)
(3)-(2)
3x-6z=3
x-2z=1(5)
(4)+(5)
2x=4
x=2
代入(4)
2+2z=3
z=1/2
代入(2)
y+1=-2
y=-3
所以
x=2,y=-3,z=1/2
解三元一次方程组2x-y+2z=8,y+2z=-2,3x+y-4z=1
解三元一次方程组2x-y+2z=8,y+2z=-2,3x+y-4z=1
数学人气:951 ℃时间:2020-01-09 05:57:22
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