(2根号3-2)(3根号6+根号2)+(3根号3+5根号2)÷(3根号3-5根号2)化简

(2√3-2)(3√6+√2)+(3√3+5√2)/(3√3-5√2)=2(√3-1)*√2(3√3+1)+[(3√3+5√2)(3√3+5√2)]/[(3√3-5√2)(3√3+5√2)]=2√2(9-3√3+√3-1)+(27+50+30√6)/(27-50)=2√2(8-2√3)-(77+30√6)/23=16√2-4√6-77/23-3...好复杂是有点复杂