化简代数式[(a^2+b^2)/(a^2-b^2)]/[2ab/(a-b)(a+b)^2]

=(a²+b²)/(a+b)(a-b) ×(a-b)(a+b)²/2ab
=(a+b)(a²+b²)/2abp=(x^2)/(x-y)+(y^2)/(y-x),q=(x-y)^2+(x+y)小敏、小聪两人分别计算了p和q的值,p大还是q大，为什么，说明理由p=x²/(x-y)-y²/(x-y) =(x²-y²)/(x-y) =(x+y)∵(x-y)²>=0∴p<=Q