已知M N为整数且满足方程2M的平方;+N的平方+3M+N-1=0 求M N的值

2M^2+N^2+3M+N-1=2(M+3/4)^2-2*(3/4)^2 +(N+1/2)^2-(1/2)^2-1=2(M+3/4)^2 + (N+1/2)^2 -9/8-1/4-1=2(M+3/4)^2 + (N+1/2)^2 -19/8=02(M+3/4)^2 + (N+1/2)^2 =19/8[(N+1/2)^2]min=1/4 [2(M+3/4)^2]min=1/8(当M=-1) 2(M...