设q的绝对值小于1,证明q的n次方的极限是0.求具体证明过程
设q的绝对值小于1,证明q的n次方的极限是0.求具体证明过程
数学人气:923 ℃时间:2019-10-23 04:13:43
优质解答
q=0时显然成立.q≠0时,│q^n-0│=│q│^n 任给正数ε>0,要使│q│^n N时,就有│q│^n
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