如图,BE⊥AC,CD⊥AB,且AD=AE,求证:DF=EF.
如图,BE⊥AC,CD⊥AB,且AD=AE,求证:DF=EF.
数学人气:395 ℃时间:2019-10-10 06:35:38
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证明:∵BE⊥AC,CD⊥AB,∴∠BEA=∠BEC=90°,∠CDA=∠CDB=90°,在△ADC和△AEC中∠ADC=∠AECAD=AE∠A=∠A,∴△ADC≌△AEC(ASA),∴AB=AC,∠B=∠C,∵AD=AE,∴AB-AD=AC-AE,即BD=CE,在△BDF和△CEF中∠B...
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