f(x)=(x^2-3x+2/x^2-x-2)^2 求它的反函数

令f(x)=y (看起来方便一点）y=(x^2-3x+2/x^2-x-2)^2 =[(x-1)(x-2)/(x+1)(x-2)]^2y=[(x-1)/(x+1)]^2√y=(x-1)/(x+1) 或-√y=(x-1)/(x+1)√y×(x+1)=(x-1)√yx+√y-x=-1(1-√y)x=(1+√y)x=(1+√y)/(1-√y)或-√y×(x+1...